document.write( "Question 184869: Use slope intercept to graph the equation. I don't know what my points should be!\r
\n" ); document.write( "\n" ); document.write( "y=8/7x-1
\n" ); document.write( "

Algebra.Com's Answer #138749 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Your equation is already in the \"slope-intercept\" form of y = mx+b
\n" ); document.write( "\"y+=+%288%2F7%29x-1\" where the slope, \"m+=+8%2F7\" and the y-intercept is \"b+=+-1\"
\n" ); document.write( "Now this is a linear equation, which means it will graph into a straight line, and you need only two points to define a straight line.
\n" ); document.write( "To get those two points, you first set x = 0 and solve the equation for y, then you set y = 0 and solve the equation for x, like this...
\n" ); document.write( "\"y+=+%288%2F7%29x-1\" Set x = 0 and solve for y.
\n" ); document.write( "\"y+=+%288%2F7%29%280%29-1\"
\n" ); document.write( "\"y+=+-1\" So the first point is (0, -1)
\n" ); document.write( "\"y+=+%288%2F7%29x-1\" Set y = 0 and solve for x.
\n" ); document.write( "\"0+=+%288%2F7%29x-1\" Add 1 to both sides.
\n" ); document.write( "\"1+=+%288%2F7%29x\" Now multiply both sides by the multiplicative inverse of \"8%2F7\" and this is \"7%2F8\"
\n" ); document.write( "\"1%287%2F8%29+=+x\" The second point is (7/8, 0)
\n" ); document.write( "Now plot these two points on your coordinate graph paper and joint the point with a straight.
\n" ); document.write( "\"graph%28400%2C400%2C-5%2C5%2C-5%2C5%2C%288%2F7%29x-1%29\"
\n" ); document.write( "
\n" );