document.write( "Question 184854: The rate of one plane is 80 kilometers an hour less than taht of a second. If the first plane takes 6 2/3 hours to travel the same distance that the second plane travels in 4 hours, find the rate of each. \n" ); document.write( "
Algebra.Com's Answer #138728 by ankor@dixie-net.com(22740)\"\" \"About 
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The rate of one plane is 80 kilometers an hour less than that of a second.
\n" ); document.write( " If the first plane takes 6 2/3 hours to travel the same distance that the
\n" ); document.write( " second plane travels in 4 hours, find the rate of each.
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\n" ); document.write( "Let r = rate of the slow plane
\n" ); document.write( "then
\n" ); document.write( "(r+80) = rate of the fast plane
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\n" ); document.write( "make 6 2/3 hrs into an improper fraction, namely \"20%2F3\" hrs
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\n" ); document.write( "Write a distance equation: Dist = time * speed
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\n" ); document.write( "slow plane dist = Fast plane dist
\n" ); document.write( "\"20%2F3\"r = 4(r+80)
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\n" ); document.write( "Mult both sides by 3 to get rid of the denominator
\n" ); document.write( "20r = 12(r+80)
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\n" ); document.write( "20r = 12r + 960
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\n" ); document.write( "20r - 12r = 960
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\n" ); document.write( "8r = 960
\n" ); document.write( "r = \"960%2F8\"
\n" ); document.write( "r = 120 km/hr is the 1st plane
\n" ); document.write( "and
\n" ); document.write( "120 + 80 = 200 km/hr is the 2nd plane
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\n" ); document.write( "Check solutions by finding the distances
\n" ); document.write( "\"20%2F3\" * 120 = 800 km
\n" ); document.write( "4 * 200 = 800km; confirms our solution
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