document.write( "Question 184854: The rate of one plane is 80 kilometers an hour less than taht of a second. If the first plane takes 6 2/3 hours to travel the same distance that the second plane travels in 4 hours, find the rate of each. \n" ); document.write( "
Algebra.Com's Answer #138728 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! The rate of one plane is 80 kilometers an hour less than that of a second. \n" ); document.write( " If the first plane takes 6 2/3 hours to travel the same distance that the \n" ); document.write( " second plane travels in 4 hours, find the rate of each. \n" ); document.write( ": \n" ); document.write( "Let r = rate of the slow plane \n" ); document.write( "then \n" ); document.write( "(r+80) = rate of the fast plane \n" ); document.write( ": \n" ); document.write( "make 6 2/3 hrs into an improper fraction, namely \n" ); document.write( ": \n" ); document.write( "Write a distance equation: Dist = time * speed \n" ); document.write( ": \n" ); document.write( "slow plane dist = Fast plane dist \n" ); document.write( " \n" ); document.write( "; \n" ); document.write( "Mult both sides by 3 to get rid of the denominator \n" ); document.write( "20r = 12(r+80) \n" ); document.write( ": \n" ); document.write( "20r = 12r + 960 \n" ); document.write( ": \n" ); document.write( "20r - 12r = 960 \n" ); document.write( ": \n" ); document.write( "8r = 960 \n" ); document.write( "r = \n" ); document.write( "r = 120 km/hr is the 1st plane \n" ); document.write( "and \n" ); document.write( "120 + 80 = 200 km/hr is the 2nd plane \n" ); document.write( "; \n" ); document.write( "; \n" ); document.write( "Check solutions by finding the distances \n" ); document.write( " \n" ); document.write( "4 * 200 = 800km; confirms our solution \n" ); document.write( " \n" ); document.write( " |