document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=184816>Question 184816</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve Problems Using Linear Systems<BR>\n" );
document.write( "17. Fran and Winston have a combined income of $80 000. One quarter of Winston's income is the same as one-sixth of Fran's income. How much does each person earn?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #138698 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=138698\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"Fran and Winston have a combined income of $80 000\" ___ F + W = 80000 ___ W = 80000-F\r<BR>\n" );
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document.write( "\"One quarter of Winston's income is the same as one-sixth of Fran's income\" ___ W/4 = F/6\r<BR>\n" );
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document.write( "substituting ___ (80000-F)/4 = F/6 ___ 20000 - (F/4) = F/6\r<BR>\n" );
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document.write( "adding F/4 ___ 20000 = 5F/12\r<BR>\n" );
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document.write( "multiplying by 12/5 ___ 48000 = F\r<BR>\n" );
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document.write( "substituting ___ W = 80000 - (48000) ___ W = 32000 </SPAN>\n" );
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