document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=184836>Question 184836</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is: y= x+7 (eq. 1)<BR>\n" );
document.write( "y= -4x-3 (eq. 2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #138683 by </B><A HREF=/tutors/aboutme.mpl?userid=jigs_ipan><B>jigs_ipan(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jigs_ipan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jigs_ipan><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=138683\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> equate the first and second equation.<BR>\n" );
document.write( "x+7=-4x-3<BR>\n" );
document.write( "x+4x=-3-7 (combine liked terms)<BR>\n" );
document.write( "5x=-10 (divide both sides by 5)<BR>\n" );
document.write( "x=-2\r<BR>\n" );
document.write( "\n" );
document.write( "subtitute the value of x to any of the two equation to find y.<BR>\n" );
document.write( "y=x+7 (eq. 1)<BR>\n" );
document.write( "y=(-2)+7 (subtituting the value of x)<BR>\n" );
document.write( "y=5 </SPAN>\n" );
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