document.write( "Question 184823This question is from textbook
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document.write( ": A welder requires 25 hrs to do a job on his own. After a welder and apprentice work on job together for 10 hours, the welder goes to another job. The apprentice finishes the job in 17 more hours. How long would it take the apprentice to do the whole job alone \n" );
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Algebra.Com's Answer #138681 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A welder requires 25 hrs to do a job on his own. After a welder and apprentice \n" ); document.write( " work on job together for 10 hours, the welder goes to another job. \n" ); document.write( " The apprentice finishes the job in 17 more hours. \n" ); document.write( "How long would it take the apprentice to do the whole job alone \n" ); document.write( ": \n" ); document.write( "Let t = time required by the job by himself \n" ); document.write( ": \n" ); document.write( "Let the completed job = 1 \n" ); document.write( ": \n" ); document.write( "appren works a total 27 hrs \n" ); document.write( ": \n" ); document.write( "Welder's portion + appren portion = completed job \n" ); document.write( " \n" ); document.write( "multiply equation by 25t to get rid of the denominators, results: \n" ); document.write( "10t + 25(27) = 25t \n" ); document.write( "675 = 25t - 10t \n" ); document.write( "15t = 675 \n" ); document.write( "t = \n" ); document.write( "t = 45 hrs hrs; the appren working alone \n" ); document.write( "; \n" ); document.write( "; \n" ); document.write( "Check solution \n" ); document.write( " \n" ); document.write( ".4 + .6 = 1 \n" ); document.write( " |