document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=184718>Question 184718</A>: <I><SPAN STYLE=\"word-break: break-all;\"> use elimination method to solve.\r<BR>\n" );
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document.write( "-x+6y=-14<BR>\n" );
document.write( "3x-6y=14 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #138641 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=138641\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -x+6y=-14<BR>\n" );
document.write( "3x-6y=14<BR>\n" );
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document.write( "add the two equations together and the y terms will be eliminated:<BR>\n" );
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document.write( "+6y-6y=0.....we are left with 3x-x=0<BR>\n" );
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document.write( "2x=0<BR>\n" );
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document.write( "x=0<BR>\n" );
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document.write( "now take x's found value and plug it back into either equation<BR>\n" );
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document.write( "-0+6y=-14<BR>\n" );
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document.write( "6y=-14<BR>\n" );
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document.write( "y=-14/6=-7/3<BR>\n" );
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document.write( "(0,-7/3) </SPAN>\n" );
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