document.write( "Question 184593: I'm can't figure out how to create a quadratic equation out of the vertex and a point that it must pass through. All i've managed so far is some trial and error and come up with this.
\n" ); document.write( "y=2(x+2)²+4
\n" ); document.write( "From the vertex of (-2,4) and passing through (-1,8).
\n" ); document.write( "I have been fiddling around with it and have two ideas how to proceed.
\n" ); document.write( "I could change (x+2) to something else to move it along the x axis or change the first part of it to change the fatness or whichever you want to call it of the parabola. Regardless i figure there is a better way to do it other then trial and error, if it has been answered before i'm sorry I didn't see it. I'm self taught and this is the first time I really have had any problem. \r
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\n" ); document.write( "\n" ); document.write( "-Thanks
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Algebra.Com's Answer #138554 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
the general vertex form of a quadratic is y = a(x-h)^2 + k\r
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\n" ); document.write( "\n" ); document.write( "(h,k) is the vertex, and \"a\" controls what you call the \"fatness\"\r
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\n" ); document.write( "\n" ); document.write( "your question is basically solving for \"a\" __ algebra, not trial and error\r
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\n" ); document.write( "\n" ); document.write( "y = a(x+2)^2 + 4\r
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\n" ); document.write( "\n" ); document.write( "substituting (-1,8) ___ 8 = a(-1+2)^2 + 4\r
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\n" ); document.write( "\n" ); document.write( "subtracting 4 ___ 4 = a\r
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\n" ); document.write( "\n" ); document.write( "so the equation is ___ y = 4(x+2)^2 + 4
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