document.write( "Question 184600: Find the slope of the line being described. Graph all lines.
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Algebra.Com's Answer #138547 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\"6x-4y=16\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"-4y=16-6x\" Subtract \"6x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-4y=-6x%2B16\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-6x%2B16%29%2F%28-4%29\" Divide both sides by \"-4\" to isolate y.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28%28-6%29%2F%28-4%29%29x%2B%2816%29%2F%28-4%29\" Break up the fraction.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%283%2F2%29x-4\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "We can see that the equation \"y=%283%2F2%29x-4\" has a slope \"m=3%2F2\" and a y-intercept \"b=-4\".\r
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\n" ); document.write( "\n" ); document.write( "Now to find the slope of the perpendicular line, simply flip the slope \"m=3%2F2\" to get \"m=2%2F3\". Now change the sign to get \"m=-2%2F3\". So the perpendicular slope is \"m=-2%2F3\".\r
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\n" ); document.write( "\n" ); document.write( "Now let's use the point slope formula to find the equation of the perpendicular line by plugging in the slope \"m=3%2F2\" and the coordinates of the given point .\r
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\n" ); document.write( "\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" Start with the point slope formula\r
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\n" ); document.write( "\n" ); document.write( "\"y-6=%28-2%2F3%29%28x--4%29\" Plug in \"m=-2%2F3\", \"x%5B1%5D=-4\", and \"y%5B1%5D=6\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-6=%28-2%2F3%29%28x%2B4%29\" Rewrite \"x--4\" as \"x%2B4\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-6=%28-2%2F3%29x%2B%28-2%2F3%29%284%29\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"y-6=%28-2%2F3%29x-8%2F3\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-2%2F3%29x-8%2F3%2B6\" Add 6 to both sides. \r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-2%2F3%29x%2B10%2F3\" Combine like terms. note: If you need help with fractions, check out this solver.\r
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\n" ); document.write( "\n" ); document.write( "So the equation of the line perpendicular to \"6x-4y=16\" that goes through the point is \"y=%28-2%2F3%29x%2B10%2F3\".\r
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\n" ); document.write( "\n" ); document.write( "Here's a graph to visually verify our answer:\r
\n" ); document.write( "\n" ); document.write( "Graph of the original equation \"y=%283%2F2%29x-4\" (red) and the perpendicular line \"y=%28-2%2F3%29x%2B10%2F3\" (green) through the point .
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