document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=184596>Question 184596</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could someone please help me solve this? Thank you.\r<BR>\n" );
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document.write( "If Punxsutawney Phil sees his shadow on the first Monday in February, then legend says that winter will last 6 more weeks. In 118 years, Phil has seen his shadow 104 times. (a) What is the probability that Phil will see his shadow on a randomly chosen Groundhog Day? (b) What kind of probability is this? \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #138544 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=138544\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a)\r<BR>\n" );
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document.write( "P(see his shadow) = (number of times he's seen his shadow)/(number of times total)\r<BR>\n" );
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document.write( "P(see his shadow) = 104/118 \r<BR>\n" );
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document.write( "P(see his shadow) = 52/59\r<BR>\n" );
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document.write( "P(see his shadow) = 0.881\r<BR>\n" );
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document.write( "Multiply by 100 to get 88.1%\r<BR>\n" );
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document.write( "So the chance he'll see his shadow is 88.1%\r<BR>\n" );
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document.write( "b) \r<BR>\n" );
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document.write( "This is known as <a  rel=nofollow HREF=\"http://en.wikipedia.org/wiki/Empirical_probability\">empirical probability</a> </SPAN>\n" );
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