document.write( "Question 184550: I'm can't figure out how to create a quadratic equation out of the vertex and a point that it must pass through. All i've managed so far is some trial and error and come up with this.
\n" ); document.write( "y=2(x+2)²+4
\n" ); document.write( "From the vertex of (-2,4) and passing through (-1,8).
\n" ); document.write( "I have been fiddling around with it and have two ideas how to proceed.
\n" ); document.write( "I could change (x+2) to something else to move it along the x axis or change the first part of it to change the fatness or whichever you want to call it of the parabola. Regardless i figure there is a better way to do it other then trial and error, if it has been answered before i'm sorry I didn't see it. I'm self taught and this is the first time I really have had any problem. \r
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\n" ); document.write( "\n" ); document.write( "-Thanks
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Algebra.Com's Answer #138523 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
y=2(x+2)²+4
\n" ); document.write( "y=2(x^2+4x+4)+4
\n" ); document.write( "y=2x^2+8x+8+4
\n" ); document.write( "y=2x^2+8x+12
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+2x%5E2+%2B8x+%2B12%29+\" (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, 2x^2 +8x +12).
\n" ); document.write( "Using the x=-2 value we get:
\n" ); document.write( "y=2(-2+2)^2+4
\n" ); document.write( "y=2*0+4
\n" ); document.write( "y=4 ans.
\n" ); document.write( "(-2,4) is the vertex.
\n" ); document.write( "If x=-4 then:
\n" ); document.write( "y=2(-4+2)^2+4
\n" ); document.write( "y=2*-2^2+4
\n" ); document.write( "y=2*4+4
\n" ); document.write( "y=8+4
\n" ); document.write( "y=12
\n" ); document.write( "(-4,12) is another point on the parabola.
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