document.write( "Question 184510This question is from textbook A Survey of Mathematics with Application
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document.write( ": Set K contains 30 elements, set J contains 46 elements, and 11 elements are common to both sets. Find n ( K U J). \n" );
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Algebra.Com's Answer #138498 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! To find the number of elements in the set K U J, simply add the two sets together. However, remember to subtract the number of elements in both sets (since these elements are repeated)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In other words, use this formula:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n ( K U J) = n(K) + n(J) - n(K ∩ J)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In this case, n(K)=30, n(J)=46 and n(K ∩ J) = 11. Plug these values in to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n ( K U J) = 30 + 46 - 11\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n ( K U J) = 76 - 11\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract\r \n" ); document.write( "\n" ); document.write( "n ( K U J) = 65\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So there are 65 elements in set K U J \n" ); document.write( " |