document.write( "Question 184494: -3-4(t-5)=-2(t+3)+11
\n" ); document.write( "0.08x+0.5(x+100)=73.2
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Algebra.Com's Answer #138489 by checkley77(12844)\"\" \"About 
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-3-4(t-5)=-2(t+3)+11
\n" ); document.write( "-3-4T+20=-2T-6+11
\n" ); document.write( "-4T+2T=-6+11+3-20
\n" ); document.write( "-2T=-12
\n" ); document.write( "T=-12/-2
\n" ); document.write( "T=6 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "-3-4(6-5)=-2(6+3)+11
\n" ); document.write( "-3-24+20=-2*9+11
\n" ); document.write( "-7=-18+11
\n" ); document.write( "-7=-7
\n" ); document.write( "-----------------------
\n" ); document.write( "0.08x+0.5(x+100)=73.2
\n" ); document.write( ".08X+.05X+50=73.2
\n" ); document.write( "..58X=73.2-50
\n" ); document.write( ".58X=23.2
\n" ); document.write( "X=23.2/.58
\n" ); document.write( "X=40 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( ".08*40+.05(40+100)=73.2
\n" ); document.write( "3.2+.5*140=73.2
\n" ); document.write( "3.2+70=73.2
\n" ); document.write( "73.2=73.2\r
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