document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=184480>Question 184480</A>: <I><SPAN STYLE=\"word-break: break-all;\"> help please:don't know where to start<BR>\n" );
document.write( "3 points A(3,1, B(-1,-11) and C (-5,9) nd circle that passes through them.<BR>\n" );
document.write( "slope of line AB<BR>\n" );
document.write( "cordinate of mid point that passes through AB<BR>\n" );
document.write( "equation of perpidicular bisector of AB(1)<BR>\n" );
document.write( "show that the line corresponding to parametiic equations x=t-14,y=-1/3t is same as 1 above<BR>\n" );
document.write( "perpendicular bisector of line segment AC<BR>\n" );
document.write( "centre of circle through A,B and c<BR>\n" );
document.write( "equation of the circle <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #138486 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=138486\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> help please:don't know where to start<BR>\n" );
document.write( "3 points A(3,1, B(-1,-11) and C (-5,9) nd circle that passes through them.<BR>\n" );
document.write( "slope of line AB<BR>\n" );
document.write( "cordinate of mid point that passes through AB<BR>\n" );
document.write( "equation of perpidicular bisector of AB(1)<BR>\n" );
document.write( "show that the line corresponding to parametiic equations x=t-14,y=-1/3t is same as 1 above<BR>\n" );
document.write( "perpendicular bisector of line segment AC<BR>\n" );
document.write( "centre of circle through A,B and c<BR>\n" );
document.write( "equation of the circle <BR>\n" );
document.write( "---------------------<BR>\n" );
document.write( "Slope of the line thru A and B:<BR>\n" );
document.write( "Slope, m, = diffy/diffx<BR>\n" );
document.write( "m = (1+11)/(3+1)<BR>\n" );
document.write( "m = 3<BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "Midpoint of AB: (it's a point, it doesn't pass thru anything)<BR>\n" );
document.write( "Find the average of x and y separately.<BR>\n" );
document.write( "x1 = (3-1)/2 = 1<BR>\n" );
document.write( "y1 = (1-11)/2 = -5<BR>\n" );
document.write( "--> the midpoint is (1,-5)<BR>\n" );
document.write( "---------------------------<BR>\n" );
document.write( "equation of perpidicular bisector of AB(1):<BR>\n" );
document.write( "Lines perpendicular to AB will have a slope that's the negative inverse of AB's slope, -1/3.<BR>\n" );
document.write( "Then use<BR>\n" );
document.write( "y-y1 = m*(x-x1) where (x1,y1) is the midpoint.<BR>\n" );
document.write( "y+5 = (-1/3)*(x-1)<BR>\n" );
document.write( "y = (-1/3)x -14/3 slope-intercept form<BR>\n" );
document.write( "x+3y = -14 standard form<BR>\n" );
document.write( "-----------------------<BR>\n" );
document.write( "show that the line corresponding to parametiic equations x=t-14,y=-1/3t is same as 1 above<BR>\n" );
document.write( "x=t-14<BR>\n" );
document.write( "y=-1/3t<BR>\n" );
document.write( "Eliminate t by substitution<BR>\n" );
document.write( "x=t-14<BR>\n" );
document.write( "t = x+14<BR>\n" );
document.write( "y = (-1/3)*(x+14)<BR>\n" );
document.write( "y = (-1/3)x - 14/3  Same as above.<BR>\n" );
document.write( "-----------------------------<BR>\n" );
document.write( "perpendicular bisector of line segment AC<BR>\n" );
document.write( "Do this one as I did the one above.<BR>\n" );
document.write( "--------------------<BR>\n" );
document.write( "The rest later.<BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );