document.write( "Question 184419: a jar of nickels and dimes contains 5.45. there are 8 more dimes than nickles. How many of each are there? \n" ); document.write( "
Algebra.Com's Answer #138485 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=N+8 \n" ); document.write( ".05N+.10D=5.45 \n" ); document.write( ".05N+.10(N+8)=5.45 \n" ); document.write( ".05N+.10N+.8=5.45 \n" ); document.write( ".15N=5.45-.8 \n" ); document.write( ".15N=4.65 \n" ); document.write( "N=4.65/.15 \n" ); document.write( "N=31 IS THE NUMBER OF NICKELS. \n" ); document.write( "D=31+8=39 DIMES. \n" ); document.write( "PROOF: \n" ); document.write( ".05*31+.10*39=5.45 \n" ); document.write( "1.55+3.90=5.45 \n" ); document.write( "5.45=5.45 \n" ); document.write( " \n" ); document.write( " |