document.write( "Question 184479: the tens digit of a number is 3 less than the units digit. if the number is divided by the sum of the digits. the quotient is 4, the remainder is 3, what is the original number? \n" ); document.write( "
Algebra.Com's Answer #138468 by stanbon(75887)\"\" \"About 
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the tens digit of a number is 3 less than the units digit. if the number is divided by the sum of the digits. the quotient is 4, the remainder is 3, what is the original number?
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\n" ); document.write( "Let the original number be 10t+u
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\n" ); document.write( "Equations:
\n" ); document.write( "t = u - 3
\n" ); document.write( "(10t+u)/(t+u) = 4 + 3/(t+u)
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\n" ); document.write( "Simplify the 2nd equation:
\n" ); document.write( "10t+u = 4(t+u) + 3
\n" ); document.write( "10t+u = 4t+4u + 3
\n" ); document.write( "6t - 3u = 3
\n" ); document.write( "2t -u = 1
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\n" ); document.write( "Form the system of two equations:
\n" ); document.write( "t = u -3
\n" ); document.write( "2t -u = 1
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\n" ); document.write( "Substitute to solve for \"u\":
\n" ); document.write( "2(u-3)-u = 1
\n" ); document.write( "2u-6-u = 1
\n" ); document.write( "u = 7
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\n" ); document.write( "Substitute into t = u-3 to solve for \"t\":
\n" ); document.write( "t = 7-3 = 4
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\n" ); document.write( "The number is 47
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\n" ); document.write( "Cheers,
\n" ); document.write( "San H.
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