document.write( "Question 184308: 2/y+1=-4y/2y+2+3 \n" ); document.write( "
Algebra.Com's Answer #138437 by Alan3354(69443)\"\" \"About 
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2/y+1=-4y/2y+2+3
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\n" ); document.write( "You have to clarify this.
\n" ); document.write( "Is it (2/y) + 1? Or 2/(y+1)?
\n" ); document.write( "(-4y/2y) = -2, is that what you meant? Or 4y/(2y+2+3)?\r
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