document.write( "Question 184380: 1/5x + 3/2 = 3/10\r
\n" ); document.write( "\n" ); document.write( "Would I find the common denominator for 1/5x and 3/2, which should be 10? Then do the recipocal of 3/2 to 2/3 and then subtract 3/10-2/3? \n" ); document.write( "
Algebra.Com's Answer #138425 by checkley77(12844)\"\" \"About 
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1/5x + 3/2 = 3/10
\n" ); document.write( "x/5+3/2=3/10
\n" ); document.write( "x/5=3/10-3/2
\n" ); document.write( "x/5=(3-3*5)/10
\n" ); document.write( "x/5=(3-15)/10
\n" ); document.write( "x/5=-12/10
\n" ); document.write( "10x=-12*5
\n" ); document.write( "10x=-60
\n" ); document.write( "x=-60/10
\n" ); document.write( "x=-6 ans.
\n" ); document.write( "Proof:
\n" ); document.write( "-6/5+3/2=3/10
\n" ); document.write( "(-6*2+3*5)/(5*2)=3/10
\n" ); document.write( "(-12+15)/10=3/10
\n" ); document.write( "3/10=3/10\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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