document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=184408>Question 184408</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bill and Sally go climbing together. Sally begins 30 minutes b efore Bill at 1pm. Sally averages 18 fee/min and bill averages 20 feet/min. What time will Bill catch Sally? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #138412 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=138412\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 18T=20(T-30)<BR>\n" );
document.write( "18T=20T-600<BR>\n" );
document.write( "18T-20T=-600<BR>\n" );
document.write( "-2T=-600<BR>\n" );
document.write( "T=-600/-2<BR>\n" );
document.write( "T=300 MINUTES AFTER SALLY STARTS BILL WILL CATCH UP WITH HER.<BR>\n" );
document.write( "OR 1+5=6 PM. THEY WILL MEET.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "18*300=20(300-30)<BR>\n" );
document.write( "5,400=20*330<BR>\n" );
document.write( "5,400=5,400 FEET UP THE CLIMB THEY WILL MEET.<BR>\n" );
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