document.write( "Question 184409: Marilou leaves the house at 7:00 for a bike ride and she pedales at an average speed of 15km/h.Her dad, leaves the house at 9:15.He tales the same track as marilouu, but he is in a car traveling at an average speed of 40km/h.Whan will marilou overtake her dad???????????????? pleaseeeeeeeeeeee helpppppppppppppppppppppppppppppppppppppppppppppppppp !!!!!!!!!!!!!!!! \n" ); document.write( "
Algebra.Com's Answer #138409 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 15T=40(T-2.25) \n" ); document.write( "15T=40T-90 \n" ); document.write( "15T-40T=-90 \n" ); document.write( "-25T=-90 \n" ); document.write( "T=-90/-25 \n" ); document.write( "T=3.6 HOURS AFTER MARILOU LEAVES THE HOUSE, HER DAD WILL OVERTAKE HER. \n" ); document.write( "PROOF \n" ); document.write( "15*3.6=40(3.6-2.25) \n" ); document.write( "54=40*1.35 \n" ); document.write( "54=54 KM. WHEN THEY WILL MEET. \n" ); document.write( " |