document.write( "Question 184409: Marilou leaves the house at 7:00 for a bike ride and she pedales at an average speed of 15km/h.Her dad, leaves the house at 9:15.He tales the same track as marilouu, but he is in a car traveling at an average speed of 40km/h.Whan will marilou overtake her dad???????????????? pleaseeeeeeeeeeee helpppppppppppppppppppppppppppppppppppppppppppppppppp !!!!!!!!!!!!!!!! \n" ); document.write( "
Algebra.Com's Answer #138409 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
15T=40(T-2.25)
\n" ); document.write( "15T=40T-90
\n" ); document.write( "15T-40T=-90
\n" ); document.write( "-25T=-90
\n" ); document.write( "T=-90/-25
\n" ); document.write( "T=3.6 HOURS AFTER MARILOU LEAVES THE HOUSE, HER DAD WILL OVERTAKE HER.
\n" ); document.write( "PROOF
\n" ); document.write( "15*3.6=40(3.6-2.25)
\n" ); document.write( "54=40*1.35
\n" ); document.write( "54=54 KM. WHEN THEY WILL MEET.
\n" ); document.write( "
\n" );