document.write( "Question 184407: Evaluate the logarithm.
\n" ); document.write( "log 0.01
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Algebra.Com's Answer #138408 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\".01+=+10%5E%28-2%29\"
\n" ); document.write( "\"log%28.01%29+=+log%2810%5E%28-2%29%29\"
\n" ); document.write( "From the general rule:
\n" ); document.write( "\"log%28a%2Cb%5Ec%29+=+c%2Alog%28a%2Cb%29\"
\n" ); document.write( "\"log%2810%5E%28-2%29%29+=+%28-2%29%2Alog%2810%29\"
\n" ); document.write( "Note that
\n" ); document.write( "\"log%2810%29+=+1\"
\n" ); document.write( "\"log%2810%5E%28-2%29%29+=+%28-2%29%2A1\"
\n" ); document.write( "\"log%28.01%29+=+-2\" answer
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