document.write( "Question 184292: In 1992, the FAA conducted 86,991 pre-employment drug tests on job applicants who were to be engaged in safety and security-related jobs, and found that 1,143 were positive. (a) Construct a 95 percent confidence interval for the population proportion of positive drug tests. (b) Why is the normality assumption not a problem, despite the very small value of p? (Data are from Flying 120,no. 11 [November 1993], p. 31.) \n" ); document.write( "
Algebra.Com's Answer #138334 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! In 1992, the FAA conducted 86,991 pre-employment drug tests on job applicants who were to be engaged in safety and security-related jobs, and found that 1,143 were positive \n" ); document.write( "--- \n" ); document.write( "The sample proportion is 1143/86991 = 0.01314 \n" ); document.write( " \n" ); document.write( "(a) Construct a 95 percent confidence interval for the population proportion of positive drug tests. \n" ); document.write( "E = z*sqrt(pq/n) \n" ); document.write( "E = 1.96*sqrt(0.01314*0.98686/86991) = 0.000757 \n" ); document.write( "------- \n" ); document.write( "95% CI: 0.01314-0.000757 < p < 0.01314+0.000757 \n" ); document.write( "============================================================ \n" ); document.write( "(b) Why is the normality assumption not a problem, despite the very small value of p? \n" ); document.write( "n is large \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |