document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=184302>Question 184302</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of three consecutive odd integers is 69. Find the integers.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #138330 by </B><A HREF=/tutors/aboutme.mpl?userid=jigs_ipan><B>jigs_ipan(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jigs_ipan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jigs_ipan><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=138330\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let:<BR>\n" );
document.write( " x be the first odd integer<BR>\n" );
document.write( " x + 2 be the 2nd odd integer<BR>\n" );
document.write( " x + 4 be the 3rd odd integer<BR>\n" );
document.write( "solution:<BR>\n" );
document.write( " 1st odd integer + 2nd odd integer + 3rd odd integer = 69<BR>\n" );
document.write( " x + (x+2) + (x+4)= 69<BR>\n" );
document.write( " 3x + 6 = 69<BR>\n" );
document.write( " 3x = 69 - 6<BR>\n" );
document.write( " 3x = 63 (dividing both sides by three)<BR>\n" );
document.write( " x = 21<BR>\n" );
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document.write( " x=21<BR>\n" );
document.write( " x+2=23<BR>\n" );
document.write( " x+4=25\r<BR>\n" );
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document.write( "therefore, the 1st integer is 21, the 2nd is 23 and the 3rd is 25... </SPAN>\n" );
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