document.write( "Question 25688: Help Please\r
\n" ); document.write( "\n" ); document.write( "Here is my question: The four oldest people in golden City have lived a total of 384 years put together. The difference in ages for the youngest and the second oldest is 14. The second youngest is 3 years older than the youngest. the oldest is 20 years older than the average of the second oldest and youngest. What are their ages? \r
\n" ); document.write( "\n" ); document.write( "I keep coming up with 68 years as the youngest but it doesn't work into the problem - Where am I going wrong? Please help - daddy's daughter \n" ); document.write( "
Algebra.Com's Answer #13833 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Let the youngest be \"x\"
\n" ); document.write( "2nd youngest is \"x+3\"
\n" ); document.write( "2nd oldest is \"x+14\"
\n" ); document.write( "oldest is [x+(x+14)]/2 + 20 =x+27
\n" ); document.write( "EQUATION:
\n" ); document.write( "x + x+3 + x+14 + x+27 = 384
\n" ); document.write( " 4x + 44 = 384
\n" ); document.write( " 4x = 340
\n" ); document.write( " x = 85 (youngest)
\n" ); document.write( " x+3 = 88 next youngest
\n" ); document.write( " x+14=99 (2nd oldest)
\n" ); document.write( " x+27= 112 (oldest)\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( " \n" ); document.write( "
\n" );