document.write( "Question 184230: please help me solve each system of equation
\n" ); document.write( "1.) y=3x-4 2.) x-2y=-14 3.) x+2y=4 4.) 3x-y=2
\n" ); document.write( " y=-2x+1 y+2x=4 2x+y=-1 y=2x-5\r
\n" ); document.write( "\n" ); document.write( "and whats the solution??
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Algebra.Com's Answer #138322 by jeselle(2)\"\" \"About 
You can put this solution on YOUR website!
by substitution:
\n" ); document.write( "1.)
\n" ); document.write( "y=3x-4
\n" ); document.write( "y=-2x+1
\n" ); document.write( "simply substitute the value of y in the second equation to the first
\n" ); document.write( "-2x+1=3x-4
\n" ); document.write( "-2x-3x=-4-1
\n" ); document.write( "-5x=-5
\n" ); document.write( "(divide both sides by -5)
\n" ); document.write( "x=1
\n" ); document.write( "by elimination
\n" ); document.write( "-3x+y=-4
\n" ); document.write( " 2x+y=1
\n" ); document.write( "(subtract so that the sign of the subtrahend will be the opposite)
\n" ); document.write( " -3x+y=-4
\n" ); document.write( " -1(2x+y=1)-1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-3x+y=-4
\n" ); document.write( "-2x-y=-1\r
\n" ); document.write( "\n" ); document.write( "then add\r
\n" ); document.write( "\n" ); document.write( "-5x=-5
\n" ); document.write( "x=1
\n" ); document.write( "do the same with the others and try practicing.^^
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