document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=184289>Question 184289</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a square is numerically 3 less than the perimeter. Find the length of the side, if this length is greater than 1 unit. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #138310 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=138310\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area of a square is numerically 3 less than the perimeter.<BR>\n" );
document.write( " Find the length of the side, if this length is greater than 1 unit.<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Let s = length of a side<BR>\n" );
document.write( "then<BR>\n" );
document.write( "s^2 = area<BR>\n" );
document.write( ";<BR>\n" );
document.write( "s^2 = 4s - 3<BR>\n" );
document.write( ":<BR>\n" );
document.write( "s^2 - 4s + 3 = 0<BR>\n" );
document.write( "Factor<BR>\n" );
document.write( "(s-3)(s-1) = 0<BR>\n" );
document.write( "Greater than 1 solution<BR>\n" );
document.write( "s = 3 units<BR>\n" );
document.write( ":<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Check: 3^2 = 4(3) - 3<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );