document.write( "Question 184271This question is from textbook College Algebra
\n" ); document.write( ": A lot is in the shape of a right triangle. The shorter leg measures 120 m. The hypotenuse is 40 m longer than the length of the longer leg. How long is the longer leg?
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Algebra.Com's Answer #138287 by stanbon(75887)\"\" \"About 
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A lot is in the shape of a right triangle. The shorter leg measures 120 m. The hypotenuse is 40 m longer than the length of the longer leg. How long is the longer leg? \r
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\n" ); document.write( "Let the longer leg be \"x\" m in length.
\n" ); document.write( "Then the hypotenuse is \"x+40\" m
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\n" ); document.write( "Equation:
\n" ); document.write( "(x+40)^2 = x^2 + 120^2
\n" ); document.write( "x^2 + 80x + 6400 = x^2 = 14400
\n" ); document.write( "x^2 + 79x - 8000 = 0\r
\n" ); document.write( "\n" ); document.write( "x = [-79 +- sqrt(79^2 - 4*-8000)]/2\r
\n" ); document.write( "\n" ); document.write( "Positive solution:\r
\n" ); document.write( "\n" ); document.write( "x = [-79 + sqrt(38241)]/2\r
\n" ); document.write( "\n" ); document.write( "x = 58.28 (longer leg)
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\n" ); document.write( "Cheers,
\n" ); document.write( "San H.
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