document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=184253>Question 184253</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a collection of dimes and nickels contains 37 coins and has a total value of $2.85.how many of each coin are there in the collection? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #138267 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=138267\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> N+D=37 OR N=37-D<BR>\n" );
document.write( ".05N+.10D=2.85<BR>\n" );
document.write( "NOW REPLACE N IN THE SECOND EQUATION WITH (37-D) & SOLVE FOR THR NUMBER OF DIMES.<BR>\n" );
document.write( ".05(37-D)+.10D=2.85<BR>\n" );
document.write( "1.85-.05D+.10D=2.85<BR>\n" );
document.write( ".05D=2.85-1.85<BR>\n" );
document.write( ".05D=1.00<BR>\n" );
document.write( "D=1.00/.05<BR>\n" );
document.write( "D=20 NUMBER OF DIMES.<BR>\n" );
document.write( "N=37-20=17 IS THE NUMBER OF NICKELS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( ".05*17+.10*20=2.85<BR>\n" );
document.write( ".85+2.00=2.85<BR>\n" );
document.write( "5.85=5.85<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );