document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=25724>Question 25724</A>: <I><SPAN STYLE=\"word-break: break-all;\">   We are working with substitution and elimination right now on story problems to solve systems of linear equations.  I am not sure how you use ratios in equations like that.  This is the problem:\r<BR>\n" );
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document.write( "Kay spends 250 min/wk exercising.  Her ratio of time spent on aerobics to time spent on weight training is 3 to 2.  How many minutes per week does she spend on aerobics?  How many minutes per week does she spend on weight training?\r<BR>\n" );
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document.write( "  I'm sorry if this is already posted somewhere.  I'm just not sure how to work the ratios into the equation.  Thank you!!   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13826 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13826\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = number of minutes on aerobics.<BR>\n" );
document.write( "y = number of minutes on weight training\r<BR>\n" );
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document.write( "You need two equations:<BR>\n" );
document.write( "x+y = 250\r<BR>\n" );
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document.write( "Then, set up a ratio <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%28aerobics%29%2F%28weight+training%29+=3%2F2=x%2Fy ALIGN=MIDDLE  ALT=\"+%28aerobics%29%2F%28weight+training%29+=3%2F2=x%2Fy\"   DISABLED_style= \"max-width:90%; height:auto;\" >, from which you  get:<BR>\n" );
document.write( "2x = 3y\r<BR>\n" );
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document.write( "x+y = 250<BR>\n" );
document.write( "2x - 3y = 0\r<BR>\n" );
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document.write( "Multiply the first equation by 3:\r<BR>\n" );
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document.write( "3x + 3y = 750<BR>\n" );
document.write( "2x - 3y = 0<BR>\n" );
document.write( "5x = 750<BR>\n" );
document.write( "x= 150 hours aerobics<BR>\n" );
document.write( "y = 100 hours weight training\r<BR>\n" );
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document.write( "R^2 at SCC\r<BR>\n" );
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document.write( " </SPAN>\n" );
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