document.write( "Question 184227This question is from textbook
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document.write( ": A student walks and jogs to college each day. She averages 5 km/h walking and 9km/h jogging. The distance from home to college is 8 km, and she makes the trip in 1 hr. How far does the student jog? \n" );
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Algebra.Com's Answer #138259 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A student walks and jogs to college each day. She averages 5 km/h walking and 9km/h jogging. The distance from home to college is 8 km, and she makes the trip in 1 hr. How far does the student jog? \n" ); document.write( "--------------- \n" ); document.write( "Walking DATA: \n" ); document.write( "distance = x km ; rate = 5 km/h ; time = d/r = x/5 hr \n" ); document.write( "-------------------- \n" ); document.write( "Jogging DATA: \n" ); document.write( "distance = (8-x) km ; rate = 9 km/h ; time = (8-x)/9 hr \r \n" ); document.write( "\n" ); document.write( "============= \n" ); document.write( "Equation \n" ); document.write( "time + time = 1 hr \n" ); document.write( "x/5 + (8-x)/9 = 1\r \n" ); document.write( "\n" ); document.write( "Multiply thru by 45 to get: \n" ); document.write( "9x + 5(8-x) = 45 \n" ); document.write( "9x + 40 - 5x = 45 \n" ); document.write( "4x = 5 \n" ); document.write( "x = 5/4 km (walking distance \n" ); document.write( "----- \n" ); document.write( "8-x = 8 -5/4 = 27/4 km (jogging distance) \n" ); document.write( "================================================= \n" ); document.write( "Cheers \n" ); document.write( "Stan H. \n" ); document.write( " |