document.write( "Question 184199This question is from textbook
\n" ); document.write( ": This is a teacher generated question.\r
\n" ); document.write( "\n" ); document.write( "How many liters of a 30% alcohol solution must be mixed with 80 liters of a 80% solution to get a 40% solution.\r
\n" ); document.write( "\n" ); document.write( "I've tried the following, but I'm not sure it's right at all. \r
\n" ); document.write( "\n" ); document.write( "a+b=80L
\n" ); document.write( "30a+80b=3200
\n" ); document.write( "Multiply by -30 to use the elimination format, this give you:\r
\n" ); document.write( "\n" ); document.write( "-30a - 30b = -2400L
\n" ); document.write( "30a + 80b = 3200L\r
\n" ); document.write( "\n" ); document.write( " 50b = 800
\n" ); document.write( " b=16L, which makes a = 64L \r
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Algebra.Com's Answer #138240 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
AT LEAST YOU GAVE IT A TRY BUT I CAN'T FOLLOW WHAT YOU DID BECAUSE I'M NOT SURE WHAT a AND b REPRESENT. ANYWAY, SEE IF YOU CAN FOLLOW WHAT I DID. NICE TRY!!!!!
\n" ); document.write( "Let x=number of liters of 30% solution needed
\n" ); document.write( "Now we know that the pure alcohol in the 30% solution (0.30x) plus the amount of pure alcohol in the 80% solution (0.80*80) has to equal the amount of pure alcohol in the final mixture (0.40(80+x)), so our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "0.30x+0.80*80=0.40(80+x) get rid of parens
\n" ); document.write( "0.30x+64=32+0.40x subtract 64 and also 0.40x from each side
\n" ); document.write( "0.30x-0.40x+64-64=32-64+0.40x-0.40x collect like terms
\n" ); document.write( "-0.10x=-32 divide each side by -0.10
\n" ); document.write( "x=320 liters----------------------ans\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "0.30*320+0.80*80=0.40*400
\n" ); document.write( "96+64=160
\n" ); document.write( "160=160\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
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