document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=25724>Question 25724</A>: <I><SPAN STYLE=\"word-break: break-all;\">   We are working with substitution and elimination right now on story problems to solve systems of linear equations.  I am not sure how you use ratios in equations like that.  This is the problem:\r<BR>\n" );
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document.write( "Kay spends 250 min/wk exercising.  Her ratio of time spent on aerobics to time spent on weight training is 3 to 2.  How many minutes per week does she spend on aerobics?  How many minutes per week does she spend on weight training?\r<BR>\n" );
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document.write( "  I'm sorry if this is already posted somewhere.  I'm just not sure how to work the ratios into the equation.  Thank you!!   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13824 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13824\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> aerobics to weight =3:2<BR>\n" );
document.write( "So represent aerobics time as 3x and weight train as 2x<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "3x+2x=250 min<BR>\n" );
document.write( "5x=250<BR>\n" );
document.write( " x=50<BR>\n" );
document.write( "aerobics is 3x=150 min<BR>\n" );
document.write( "Weight train is 2x=100 min\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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