document.write( "Question 184155: A jet, traveling at an average speed of 420 miles per hour in still air, flew 240 miles and back in 1 hour and 10 minutes. What is the average speed of the wind in mph? \n" ); document.write( "
Algebra.Com's Answer #138220 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r\r
\n" ); document.write( "\n" ); document.write( "Let s=speed of the wind
\n" ); document.write( "With the wind, add wind speed; against the wind subtract
\n" ); document.write( "Time travelling with the wind= 240/(420+s)
\n" ); document.write( "Time travelling against the wind=240/(420-s)
\n" ); document.write( "Now we are told that the above two times add up to 1 hr 10min=1 1/6=7/6 hr so:
\n" ); document.write( "240/(420+s) +240/(420-s)=7/6 multiply each term by 6(420+s)(420-s)
\n" ); document.write( "1440(420-s)+1440(420+s)=7(420+s)(420-s) get rid of parens
\n" ); document.write( "1440*420-1440s+1440*420+1440s=7*176400-7s^2
\n" ); document.write( "YOU KNOW, THERE MAY BE AN EASIER WAY BUT THE ONLY THING I CAN SEE TO DO RIGHT NOW IS GRIND OUT THE BIG NUMBERS.\r
\n" ); document.write( "\n" ); document.write( "604800+604800=1234800-7s^2 this equals
\n" ); document.write( "1209600=1234800-7s^2 subtract 1234800 from each side
\n" ); document.write( "-7s^2=-25200 divide each side by -7
\n" ); document.write( "s^2=3600 take square root of each side
\n" ); document.write( "s=+or- 60 mph-------------------------------------------------speed of the wind
\n" ); document.write( "disregard the negative value for s; wind speed is positive\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "240/(420+60) +240/(420-60)=7/6
\n" ); document.write( "240/480 + 240/360=7/6
\n" ); document.write( "1/2 + 2/3=7/6
\n" ); document.write( "3/6+ 4/6=7/6
\n" ); document.write( "7/6=7/6\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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