document.write( "Question 25707: Walt made an extra $9000 last year from a part-time job. He invested part of the money at a 9% annual rate of interest, and the rest at an 8% annual rate of interest. At the end of the year, he made a total of $770 in interest. How much was invested at 8%? \n" ); document.write( "
Algebra.Com's Answer #13822 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Let x = the amount invested at 9% \n" ); document.write( "Since the total amount invested was $9000, the amount invested at 8% \n" ); document.write( "can be expressed as (9000 - x) \n" ); document.write( "the interest received from the 9% investment is \n" ); document.write( ".09x \n" ); document.write( "the interest received from the 8% investment is \n" ); document.write( ".08(9000 - x) \n" ); document.write( "If you add these two interest incomes together, you get the toal interest \n" ); document.write( "that Walt made, so \n" ); document.write( ".09x + .08(9000 - x) = 770 \n" ); document.write( ".09x + 720 - .08x = 770 \n" ); document.write( ".01x = 50 \n" ); document.write( "x = 5000 \n" ); document.write( "this is the amount invested at 9% \n" ); document.write( "(9000 - 5000)= 4000 is the amount invested at 8% \n" ); document.write( " |