document.write( "Question 184145: On May 12 a snail fell to the bottom of a 20 foot deep well. Each day it crawled 3 feet up the side of the well and each night it slid back 2 feet. On what date did the snail reach the top of the well? \n" ); document.write( "
Algebra.Com's Answer #138210 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! If the snail goes up 3 and down 2 each day, then it is making 1 foot progress each day. On the morning of the 18th day, it will be 3 feet from the top because it will have made 1 foot progress each of the preceeding 17 days. On the 18th day it will get to the top and not slide down any that night. 18 days. \n" ); document.write( " |