document.write( "Question 184171: If the sides of a square are lenghtened by 8cm, the area becomes 144 cm^2. Find the length of a side of the original square. \r
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document.write( "Which form of the quadratic equation would I use to solve this problem? \n" );
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Algebra.Com's Answer #138202 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! If the sides of a square are lengthened by 8cm, the area becomes 144 cm^2. \n" ); document.write( " Find the length of a side of the original square. \n" ); document.write( "; \n" ); document.write( "Let x = side of the original square \n" ); document.write( "then \n" ); document.write( "(x+8) = side of the larger square \n" ); document.write( ": \n" ); document.write( "(x+8)^2 = 144 \n" ); document.write( "Find the square root of both sides \n" ); document.write( "x + 8 = 12 \n" ); document.write( ": \n" ); document.write( "x = 12 - 8 \n" ); document.write( ": \n" ); document.write( "x = 4 cm is the length of the original square \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check: (4+8)^2 = 144 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "If you absolutely have to have a quadratic equation: \n" ); document.write( "Foil (x+8)^2 \n" ); document.write( "x^2 + 16x + 64 = 144 \n" ); document.write( "x^2 + 16x + 64 - 144 = 0 \n" ); document.write( "x^2 + 16x - 80 = 0 \n" ); document.write( "Factor \n" ); document.write( "(x+20)(x-4) = 0 \n" ); document.write( "Positive solution is what we want: \n" ); document.write( "x = 4 cm \n" ); document.write( " |