document.write( "Question 25717: if a=b
\n" ); document.write( "then
\n" ); document.write( "a*a=a*b
\n" ); document.write( "a^2=ab
\n" ); document.write( "a^2-b^2=ab-b^2
\n" ); document.write( "(a+b)(a-b)=b(a-b)
\n" ); document.write( "a+b=b
\n" ); document.write( "a+a=a
\n" ); document.write( "2a=a
\n" ); document.write( "it contradicts the assumption..
\n" ); document.write( "what is wrong in this ?
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Algebra.Com's Answer #13820 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
When you had (a+b)(a-b)=b(a-b) you divided both sides
\n" ); document.write( "by (a-b) to get a+b=b.
\n" ); document.write( "But in doing that you divided by zero because you
\n" ); document.write( "started the argument by saying a=b.
\n" ); document.write( "Dividing by zero is an illegal move, i.e. it is
\n" ); document.write( "meaningless; so you ended up with a meaningless
\n" ); document.write( "conclusion.\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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