document.write( "Question 184163: A plane flies 900km with a tail wind in 3 hours. The same plane takes 4 hours to make the return trip against the wind. What is the speed of the plane in still air? \n" ); document.write( "
Algebra.Com's Answer #138193 by ptaylor(2198)\"\" \"About 
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\n" ); document.write( "Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r
\n" ); document.write( "Let r=speed of the plane in still air
\n" ); document.write( "Let s=speed of the wind\r
\n" ); document.write( "\n" ); document.write( "If the plane is flying with the wind, we add the wind speed;
\n" ); document.write( "Against the wind, we subtract. So:
\n" ); document.write( "r+s=900/3=300------------------------------eq1
\n" ); document.write( "r-s=900/4=225------------------------------eq2\r
\n" ); document.write( "\n" ); document.write( "add eq1 and eq2:
\n" ); document.write( "2r=525
\n" ); document.write( "r=262.5 mph---------------------speed of plane in still air
\n" ); document.write( "substitute r=262.5 mph into eq1:
\n" ); document.write( "262.5+s=300
\n" ); document.write( "s=300-262.5=37.5 mph-------------speed of the wind\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
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