document.write( "Question 183947: Translate to a system of equations and solve.\r
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document.write( "The sum of two numbers is 14. Six times the first number minus three times the second number is 3. Find the numbers. \n" );
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Algebra.Com's Answer #138158 by eperette(173)![]() ![]() ![]() You can put this solution on YOUR website! x + y = 14 \n" ); document.write( "6x - 3y = 3\r \n" ); document.write( "\n" ); document.write( "there are two ways to solve for this, i will use the elimination method: \n" ); document.write( "3( x + y = 14) \n" ); document.write( "6x - 3y = 3\r \n" ); document.write( "\n" ); document.write( "***************** \n" ); document.write( "3x + 3y = 42 \n" ); document.write( "6x - 3y = 3 \n" ); document.write( "__________________ \n" ); document.write( "9x + 0 = 45 \n" ); document.write( "9x/9 = 45/9 \n" ); document.write( "x = 5 \n" ); document.write( "then: \n" ); document.write( "x + y = 14 \n" ); document.write( "5 + y = 14 \n" ); document.write( "5 - 5 + y = 14 - 5 \n" ); document.write( "0 + y = 9\r \n" ); document.write( "\n" ); document.write( "so the numbers are: 5 and 9 \n" ); document.write( "check: \n" ); document.write( "5 + 9 = 14 \n" ); document.write( "6(5) - 3(9) = 30 - 27 = 3 \n" ); document.write( "answer is correct \n" ); document.write( " |