document.write( "Question 184097: A worker can cover a parking lot with asphalt in 10 hours. With the help of an assistant, the work can be done in 6 hours. How long would it take the assistant, working alone, to cover the parking lot with asphalt?\r
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document.write( "worker a 10(1/10)
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document.write( "worker b t(1/6)
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document.write( "10(1/10)=t(1/6)
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document.write( "I think I am setting the problem up wrong. Thank you. \n" );
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Algebra.Com's Answer #138101 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! A worker can cover a parking lot with asphalt in 10 hours. With the help of an assistant, the work can be done in 6 hours. How long would it take the assistant, working alone, to cover the parking lot with asphalt? \n" ); document.write( "------------------- \n" ); document.write( "To add the efforts, you have to get them in the same units. One person does the job in 10 hours, so he does 1/10 of the job per hour. \n" ); document.write( "The other person does 1/6 of the job per hour. \n" ); document.write( "Add 1/10 and 1/6 \n" ); document.write( "1/10 + 1/6 = 3/30 + 5/30 = 8/30 together. \n" ); document.write( "So the job take 30/8 hour = 15/4 or 3.75 hours. \n" ); document.write( "------------------------ \n" ); document.write( "A shortcut to this type of problem (with 2 only, not 3 or more) is \n" ); document.write( "product/sum \n" ); document.write( "6*10/(6+10) = 60/16 = 15/4 same answer. \n" ); document.write( " |