document.write( "Question 184082: A man rowing at the rate of 5 km/hr in still water takes thrice as much time in going 40 km upstream as he takes in going same distance downstream. find the rate at which water is flowing. \n" ); document.write( "
Algebra.Com's Answer #138093 by ankor@dixie-net.com(22740)\"\" \"About 
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A man rowing at the rate of 5 km/hr in still water takes thrice as much time in going 40 km upstream as he takes in going same distance downstream. find the rate at which water is flowing.
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\n" ); document.write( "Let x = the rate water is flowing
\n" ); document.write( "then
\n" ); document.write( "(5+x) = boat speed downstream
\n" ); document.write( "and
\n" ); document.write( "(5-x) = boat speed upstream
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\n" ); document.write( "Let d = distance one way
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\n" ); document.write( "write a time equation; Time = \"dist%2Fspeed\":
\n" ); document.write( "upstream time = 3 times downstream time
\n" ); document.write( "\"d%2F%28%285-x%29%29\" = 3(\"d%2F%28%285%2Bx%29%29\")
\n" ); document.write( "\"d%2F%28%285-x%29%29\" = \"%283d%29%2F%28%285%2Bx%29%29\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "d(5+x) = 3d(5-x)
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\n" ); document.write( "divide both sides d and eliminate it:
\n" ); document.write( "5 + x = 3(5 - x)
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\n" ); document.write( "5 + x = 15 - 3x
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\n" ); document.write( "x + 3x = 15 - 5
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\n" ); document.write( "4x = 10
\n" ); document.write( "x = \"10%2F4\"
\n" ); document.write( "x = 2.5 km/hr is the rate of the current
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\n" ); document.write( "Check solution by finding the distances, should be equal:
\n" ); document.write( " 5 + 2.5 = 7.5
\n" ); document.write( "3(5 - 2.5) = 7.5\r
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