document.write( "Question 184082: A man rowing at the rate of 5 km/hr in still water takes thrice as much time in going 40 km upstream as he takes in going same distance downstream. find the rate at which water is flowing. \n" ); document.write( "
Algebra.Com's Answer #138093 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A man rowing at the rate of 5 km/hr in still water takes thrice as much time in going 40 km upstream as he takes in going same distance downstream. find the rate at which water is flowing. \n" ); document.write( ": \n" ); document.write( "Let x = the rate water is flowing \n" ); document.write( "then \n" ); document.write( "(5+x) = boat speed downstream \n" ); document.write( "and \n" ); document.write( "(5-x) = boat speed upstream \n" ); document.write( "; \n" ); document.write( "Let d = distance one way \n" ); document.write( "; \n" ); document.write( "write a time equation; Time = \n" ); document.write( "upstream time = 3 times downstream time \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "d(5+x) = 3d(5-x) \n" ); document.write( ": \n" ); document.write( "divide both sides d and eliminate it: \n" ); document.write( "5 + x = 3(5 - x) \n" ); document.write( "; \n" ); document.write( "5 + x = 15 - 3x \n" ); document.write( ": \n" ); document.write( "x + 3x = 15 - 5 \n" ); document.write( ": \n" ); document.write( "4x = 10 \n" ); document.write( "x = \n" ); document.write( "x = 2.5 km/hr is the rate of the current \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the distances, should be equal: \n" ); document.write( " 5 + 2.5 = 7.5 \n" ); document.write( "3(5 - 2.5) = 7.5\r \n" ); document.write( "\n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |