document.write( "Question 184077: I am having a problem with a word problem for my math class. The problem is: If a basketball player has a vertical leap of about 20 inches, what is his hang time? Use the hang time function V=48T^2. Here is what the example says to do.
\n" ); document.write( "To solve for T, first multiply by 1/48 to get T^2=20/48. Because hang time is positive, you can take the positive square root get T=squart20/48. \r
\n" ); document.write( "\n" ); document.write( "I get that part, what I don't get is how did they get that T=squart20/48=0.6 seconds. How would I get the seconds if the equation is T=squart35/48?
\n" ); document.write( "

Algebra.Com's Answer #138092 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
If a basketball player has a vertical leap of about 20 inches, what is his hang time? Use the hang time function V=48T^2.
\n" ); document.write( ":
\n" ); document.write( "Use basic algebra rules to solve for T, (isolate T by itself on the left)
\n" ); document.write( "write it:
\n" ); document.write( "48T^2 = V
\n" ); document.write( ":
\n" ); document.write( "Substitute 20 for T
\n" ); document.write( "48T^2 = 20
\n" ); document.write( ":
\n" ); document.write( "Divide both sides by 48
\n" ); document.write( "T^2 = \"20%2F48\"
\n" ); document.write( ":
\n" ); document.write( "Find the square root of both sides to change T^2 to just T
\n" ); document.write( "T = \"sqrt%2820%2F48%29\"
\n" ); document.write( ":
\n" ); document.write( "Enter \"sqrt%2820%2F48%29\" into a calc, it will = .64549.. rounded to .6 sec
\n" ); document.write( ";
\n" ); document.write( "You would do it exactly the same way if it were 35/48
\n" ); document.write( ":
\n" ); document.write( "Does this make sense to you now?
\n" ); document.write( "
\n" ); document.write( "
\n" );