document.write( "Question 184077: I am having a problem with a word problem for my math class. The problem is: If a basketball player has a vertical leap of about 20 inches, what is his hang time? Use the hang time function V=48T^2. Here is what the example says to do.
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document.write( "To solve for T, first multiply by 1/48 to get T^2=20/48. Because hang time is positive, you can take the positive square root get T=squart20/48. \r
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document.write( "I get that part, what I don't get is how did they get that T=squart20/48=0.6 seconds. How would I get the seconds if the equation is T=squart35/48? \n" );
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Algebra.Com's Answer #138092 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! If a basketball player has a vertical leap of about 20 inches, what is his hang time? Use the hang time function V=48T^2. \n" ); document.write( ": \n" ); document.write( "Use basic algebra rules to solve for T, (isolate T by itself on the left) \n" ); document.write( "write it: \n" ); document.write( "48T^2 = V \n" ); document.write( ": \n" ); document.write( "Substitute 20 for T \n" ); document.write( "48T^2 = 20 \n" ); document.write( ": \n" ); document.write( "Divide both sides by 48 \n" ); document.write( "T^2 = \n" ); document.write( ": \n" ); document.write( "Find the square root of both sides to change T^2 to just T \n" ); document.write( "T = \n" ); document.write( ": \n" ); document.write( "Enter \n" ); document.write( "; \n" ); document.write( "You would do it exactly the same way if it were 35/48 \n" ); document.write( ": \n" ); document.write( "Does this make sense to you now? \n" ); document.write( " \n" ); document.write( " |