document.write( "Question 25691: I need help solving this problem \"+2+%2A+X%5E2=288+\" solve for X.\r
\n" ); document.write( "\n" ); document.write( "This is how I tried to solve it, I tried two way but I am unsure\r
\n" ); document.write( "\n" ); document.write( "2X^2=288
\n" ); document.write( "(2x)(2x)=288
\n" ); document.write( "4X=288
\n" ); document.write( "X=72 \r
\n" ); document.write( "\n" ); document.write( "Or I also tried this way \r
\n" ); document.write( "\n" ); document.write( "2*X^2=288
\n" ); document.write( "2*(X)(X)=288
\n" ); document.write( "2X=288
\n" ); document.write( "2X/2=288/2
\n" ); document.write( "X=144\r
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Algebra.Com's Answer #13808 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve for x:
\n" ); document.write( "\"2x%5E2+=+288\" Notice that only the x is squared, not the 2. Divide both sides of the eqaution by 2.
\n" ); document.write( "\"x%5E2+=+144\" Now take the square-root of both sides.
\n" ); document.write( "\"sqrt%28x%5E2%29+=+x\" and \"sqrt%28144%29+=+12\" + or -
\n" ); document.write( "x = + or - 12
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