document.write( "Question 25708: An express and local train leave GraysLake at 3 P.M. and head for Chicago 50 miles away. The express travels twice as fast as the local and arrives 1 hour ahead of the local. Find the speed of each train. \n" ); document.write( "
Algebra.Com's Answer #13807 by Paul(988)\"\" \"About 
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Let the speed of one train be x
\n" ); document.write( "Let the speed of the other be 2x
\n" ); document.write( "Since 50 miles is the distance with unknown speed = 50/x for slower train and 50/2x for the faster one.
\n" ); document.write( "EXPRESSION:
\n" ); document.write( "50/x+50/2x=1
\n" ); document.write( "50[(x)+(2x)]=(x)(2x)
\n" ); document.write( "150x=2x^2
\n" ); document.write( "2x^2-150x=0
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "a=2 , b=-150, c= 0
\n" ); document.write( "\"x=%28150%2B-sqrt%2822500-4%282%29%280%29%29%29%2F%282%282%29%29\"
\n" ); document.write( "\"x=%28150%2B-sqrt%2822500%29%29%2F4%29\" remove the negative sign
\n" ); document.write( "\"x=%28150%2Bsqrt%2822500%29%29%2F4%29\"
\n" ); document.write( "\"x=%28150%2B150%29%2F4\"
\n" ); document.write( "\"x=300%2F4\"
\n" ); document.write( "x=75
\n" ); document.write( "75(2)=150\r
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\n" ); document.write( "\n" ); document.write( "Hence, the speed of one train is 75mph and for other its 150mph.
\n" ); document.write( "Paul.
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