document.write( "Question 25708: An express and local train leave GraysLake at 3 P.M. and head for Chicago 50 miles away. The express travels twice as fast as the local and arrives 1 hour ahead of the local. Find the speed of each train. \n" ); document.write( "
Algebra.Com's Answer #13807 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! Let the speed of one train be x \n" ); document.write( "Let the speed of the other be 2x \n" ); document.write( "Since 50 miles is the distance with unknown speed = 50/x for slower train and 50/2x for the faster one. \n" ); document.write( "EXPRESSION: \n" ); document.write( "50/x+50/2x=1 \n" ); document.write( "50[(x)+(2x)]=(x)(2x) \n" ); document.write( "150x=2x^2 \n" ); document.write( "2x^2-150x=0 \n" ); document.write( " \n" ); document.write( "a=2 , b=-150, c= 0 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x=75 \n" ); document.write( "75(2)=150\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence, the speed of one train is 75mph and for other its 150mph. \n" ); document.write( "Paul. \n" ); document.write( " \n" ); document.write( " |