document.write( "Question 25705: Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have? \n" ); document.write( "
Algebra.Com's Answer #13806 by Paul(988)\"\" \"About 
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Let the number of dimes be x
\n" ); document.write( "Let the number of nickels be y
\n" ); document.write( "Nickel value times 100 = 5
\n" ); document.write( "Dime value times 100 = 10
\n" ); document.write( "5.65 times 100 = 565
\n" ); document.write( "10.45 times 100 = 1045\r
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\n" ); document.write( "\n" ); document.write( "5x+10y=565
\n" ); document.write( "5x=565-10y
\n" ); document.write( "x=113-2y (subsituition)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Dimes doubled = 2x
\n" ); document.write( "Nickles increased by 8 = y+8
\n" ); document.write( "10(2x)+5(y+8)=1045
\n" ); document.write( "20x+5y+40=1045
\n" ); document.write( "Subsitute for x
\n" ); document.write( "20(113-2y)+5y=1005
\n" ); document.write( "2260-40y+5y=1005
\n" ); document.write( "-35y=-1255
\n" ); document.write( "y=36 (rounded)
\n" ); document.write( "x=41 \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hence, there are 36 dimes and 41 nickels.
\n" ); document.write( "Paul.
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