document.write( "Question 25681: Can someone please help me with this problem? I am stumped! This is the problem: \r
\n" ); document.write( "\n" ); document.write( "Show how the quadratic formula can be expressed as: \r
\n" ); document.write( "\n" ); document.write( "\"-p%2F2\"±\"+sqrt%28+p%5E2%2F4-q+%29+\"\r
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\n" ); document.write( "\n" ); document.write( "let p=\"b%2Fa\" and q=\"c%2Fa\"\r
\n" ); document.write( "\n" ); document.write( "It says that it can be derived by \"completing\" the square of a quadratic equation. A response to this problem would really make my day!
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Algebra.Com's Answer #13802 by venugopalramana(3286)\"\" \"About 
You can put this solution on YOUR website!
\"-p%2F2\"±\"+sqrt%28+p%5E2%2F4-q+%29+\"\r
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\n" ); document.write( "\n" ); document.write( "let p=\"b%2Fa\" and q=\"c%2Fa\"\r
\n" ); document.write( "\n" ); document.write( "It says that it can be derived by \"completing\" the square of a quadratic equation. A response to this problem would really make my day! \r
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\n" ); document.write( "SUBSTITUTE IN THE ANSWER GIVEN BELOW YOUR NOMENCLATURE THAT
\n" ); document.write( " p=\"b%2Fa\" and q=\"c%2Fa\"..AND YOU WILL GET YOUR ANSWER
\n" ); document.write( "LET THE QUADRATIC BE
\n" ); document.write( " AX^2+BX+C=0...SINCE THIS IS A QUADRATIC ,A IS NOT EQUAL TO ZERO..SO DIVIDING WITH A WE GET
\n" ); document.write( "X^2+BX/A+C/A=0
\n" ); document.write( "WRITE IT AS A PERFECT SQUARE USING X^2 AND X TERMS
\n" ); document.write( "{X^2+2*X*(B/2A)+(B/2A)^2}-(B/2A)^2+C/A=0
\n" ); document.write( "{X+(B/2A)}^2=(B/2A)^2-C/A=B^2/4A^2-C/A=(B^2-4AC)/4A^2
\n" ); document.write( "TAKING SQUARE ROOT
\n" ); document.write( "X+B/2A=\"%28PLUS+OR+MINUS+sqrt%28+B%5E2-4%2AA%2AC+%29%29%2F%282%2AA%29+\"
\n" ); document.write( "OR
\n" ); document.write( "\"x+=+%28-B+%2B-+sqrt%28+B%5E2-4%2AA%2AC+%29%29%2F%282%2AA%29+\"
\n" ); document.write( "THIS IS THE GENERAL METHOD OF DERIVATION OF ROOTS OF A QUADRATIC EQUATION.
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