document.write( "Question 183949: find the dimensions of a rectangle \"a\" with the greatest area whose perimetter is 30 feet \n" ); document.write( "
Algebra.Com's Answer #138018 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "The perimeter of a rectangle is given by:\r
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\n" ); document.write( "\n" ); document.write( "The area of a rectangle is given by:\r
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\n" ); document.write( "\n" ); document.write( "Substituting from the perimeter equation:\r
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\n" ); document.write( "\n" ); document.write( "This function graphs to a parabola opening downward meaning that the vertex is a maximum. The maximum value of the function, hence the maximum area, is where the value of the first derivative is equal to zero:\r
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\n" ); document.write( "\n" ); document.write( "Set equal to zero:\r
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\n" ); document.write( "\n" ); document.write( "Hence, the maximum area rectangle for a given perimeter is a square with sides of length one-fourth of the perimeter.\r
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