document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=183949>Question 183949</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the dimensions of a rectangle \"a\" with the greatest area whose perimetter is 30 feet </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #138015 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=138015\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the dimensions of a rectangle \"a\" with the greatest area whose perimetter is 30 feet<BR>\n" );
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document.write( "Perimeter = 2(L + W)<BR>\n" );
document.write( "30 + 2(L+W)<BR>\n" );
document.write( "L+W = 15<BR>\n" );
document.write( "W = 15-L<BR>\n" );
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document.write( "Area = LW<BR>\n" );
document.write( "Substitute to get:<BR>\n" );
document.write( "Area = L(15-L)<BR>\n" );
document.write( "Area = -L^2 + 15L<BR>\n" );
document.write( "That is a quadratic with a = -1,b = 15<BR>\n" );
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document.write( "Maximum area occurs when L = -b/2a = -15/(-2) = 15/2<BR>\n" );
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document.write( "Solve for W when L = (15/2)<BR>\n" );
document.write( "W = 15 - (15/2) = 15/2<BR>\n" );
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document.write( "The Width and the Length are both 15/2 ft.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );