document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=25690>Question 25690</A>: <I><SPAN STYLE=\"word-break: break-all;\"> question:\r<BR>\n" );
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document.write( "In a triangle the measure of the second angle is one-half the measure of the first angle.  The third angle's measure if 20 degrees less than the measure of the first angle.  What are the masures of the angles?\r<BR>\n" );
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document.write( "Please help!  daddy's girl </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13801 by </B><A HREF=/tutors/aboutme.mpl?userid=askmemath><B>askmemath(368)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=askmemath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13801\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the first angle = X<BR>\n" );
document.write( "Therefore the 2nd angle becomes X/2 = 0.5X<BR>\n" );
document.write( "And the 3rd angle becomes X-20\r<BR>\n" );
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document.write( "We know that sum of angles in a triangle = 180degrees<BR>\n" );
document.write( "That means<BR>\n" );
document.write( "X + 0.5X + X-20 = 180<BR>\n" );
document.write( "Adding 20 on both sides<BR>\n" );
document.write( "2.5X = 200<BR>\n" );
document.write( "Dividing by 2.5 on both sids<BR>\n" );
document.write( "X = 80<BR>\n" );
document.write( "which means 2nd angle = 80/2 = 40<BR>\n" );
document.write( "and the third angle = 80-20 = 60\r<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "Sum of the 3 angles<BR>\n" );
document.write( "80+40+60 = 180degrees\r<BR>\n" );
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document.write( "Yay!!! </SPAN>\n" );
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