document.write( "Question 183956: The length of a rectangle is 3 feet more than twice its width, and 2 feet less than a diagonal's length. Find the length of the diagonal in simplest radical form. \n" ); document.write( "
Algebra.Com's Answer #137996 by stanbon(75887)\"\" \"About 
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The length of a rectangle is 3 feet more than twice its width, and 2 feet less than a diagonal's length. Find the length of the diagonal in simplest radical form.
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\n" ); document.write( "Let width = W.
\n" ); document.write( "Then Length = \"2W+3\"
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\n" ); document.write( "Equation:
\n" ); document.write( "diagonal^2 = leg^2 + leg^2
\n" ); document.write( "d^2 = x^2 + (2x+3)^2
\n" ); document.write( "d^2 = x^2 + 4x^2 + 12x + 9
\n" ); document.write( "d^2 = 5x^2 + 12x + 9
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\n" ); document.write( "d = sqrt(5x^2+12x+9)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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