document.write( "Question 183943: A daughter is 28 years younger than her father. In 5 years, the father will be 3 times as old as his daughter. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #137988 by jojo14344(1513)\"\" \"About 
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\n" ); document.write( "Father's Age=\"x\"
\n" ); document.write( "Daughter's Age=\"x-28\"
\n" ); document.write( "As per condition: (5 years hence)
\n" ); document.write( "\"%28x%2Bhighlight%285yrs%29%29=3%28x-28%2Bhighlight%285yrs%29%29=3%28x-23%29%29\"
\n" ); document.write( "\"x%2B5=3x-69\"
\n" ); document.write( "\"3x-x=69%2B5\"
\n" ); document.write( "\"2x=74\"---->\"cross%282%29x%2Fcross%282%29=cross%2874%2937%2Fcross%282%29\"
\n" ); document.write( "\"highlight%28x=37yrs%29\", father's Age NOW
\n" ); document.write( "\"37-28=highlight%289yrs%29\", daughter's Age NOW
\n" ); document.write( "let's check 5 yrs from now:
\n" ); document.write( "\"37%2B5=3%289%2B5%29\"
\n" ); document.write( "\"42=3%2814%29\"
\n" ); document.write( "\"42=42\"
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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